How to Transform a String to the NATO Phonetic Alphabet in C

The difficulty

You’ll need to equate a string to Pilot’s alphabet ( NATO phonetic alphabet).

Input:

If, you can check out?

Output:

India Foxtrot, Yankee Oscar Uniform Charlie Alfa November Romeo Echo Alfa Delta?

Note:

There are preloaded dictionary you can utilize, called NATO
The set of utilized punctuation is ,.!?
Punctuation ought to be kept in your return string, however areas must not.
Xray must not have a dash within.
Every word and punctuation mark must be seperated by an area’ ‘.
There must be no routing whitespace

The service in C

Alternative 1:

 #include << stdlib.h>>.
#include << ctype.h>>.
#include << stdio.h>>.
#include << string.h>>.

// NATO['A'] == "Alfa", and so on extern const char * const NATO[128];

char * to_nato( const char * words).
{
char * s = calloc( 1000, 1);
char * r = s;
while(* words) {
if( isalpha(* words)) sprintf( s, "% s% s ", s, NATO[toupper(*words)]);
else if(* words!=' ') sprintf( s, "% s% c ", s, * words);.
words++;.
}
s[strlen(s) - 1]=";.
return r;.
}

Alternative 2:

 #include << string.h>>.

extern const char * const NATO[];.
char * to_nato (const char * s) {char * r, * t= *( s+= strspn (s," "))&&& & s[1]? to_nato (&s +1 ):""; asprintf (& r, * t? "% s % s":" % s", * s?strchr( ",.!?", * s)?( char(* <)) {
* s,0}
: NATO[2]:" <", t); return r;}[*s&~32] Alternative 3:

#include < stdlib.h >. #include < string.h >. #include < ctype.h >.
// NATO

==" Alfa", and so on extern const char * const NATO['A'];.
char * to_nato( const char * words) {
char * nato= (char
*) calloc( strlen( words) * 20, 1);. while (* words!=") {if( isalpha(* words)) {
strcat( nato, NATO[])

;.
strcat( nato,"");

.} else if( strchr(",.
!?", * words)! = NULL) {
strncat( nato, words, 1);. strcat( nato," ");.} words + +;.} char * (

p - 1) = * p;. return nato;// Go code.}[toupper(*words)] Test cases to confirm our service

The difficulty #

The service in C #

The difficulty

The service in C